graph y=2cosx
@eliassaab my graph looks like this one but is shifted, is that a problem?
No, it depends which interval you are using for graphing. Notice that cos(2 x) is periodic of period \(\pi\)
1 moment, i am emailing myself the picture of my work then ill put here
Be careful cos(0) =1
and not zero
the first coordinate?
Your graph is not right as pictured. It does not go through the origin.
ok, what did i do wrong? my wave is the same, but shifted to the right
http://www.wolframalpha.com/input/?i=plot+2+cos%28+x%29 Here is the graph. My first graph was for cos(2x)
did i set up my coordinate table wrong?
that isnt the problem though, the problem is y=2cosx
Your confusing sin and cos. cos(0) =1 and not zero
That is why I gave you the second link
i see the graph, but i dont see an explamation of how to get the graph
what did i do wrong in setting up my table of coordinates?
hey man, i figured it out. cosx=cos0=1 because trig functions of quadrantal angles
y=2cosx 1.) Plug value in X, and solve to get Y this gets you your xy values 2.) x=0,pi/2, pi, 3pi/2 2pi this is what we plug in to get y value 3.) use the unit circle values, cos is x coordinate, sin is y coordinate(cos,sin) 4.) y=2cos(0), 2*1=2, so y=2, y=2cos(-1) at pi 2(-1)=-2, so y=-2 y=2cos (0), at pi/2 2*1=2, so y=2 y=2cos (0), at 3pi/2 2(1)=2, so y=2 y=2cos(1), at 2pi 2(1)=2, so y=2 5.) so x values= 0,pi,pi/2,2pi,3pi/2 y values= 2, -2, 2, 2, 2 Understand?
yes sir, i understand. that sending me to a website crap doesnt help. heck, i already went to websites before posting my question, it didnt help. posting websites doesnt help. again thank you
I agree, sorry I am a slow typer, Im glad you understand, feel free to ask me any questions!
no problem, ill be patient for a thorough explanation anyday
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