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Mathematics 28 Online
OpenStudy (anonymous):

graph y=2cosx

OpenStudy (anonymous):

@eliassaab my graph looks like this one but is shifted, is that a problem?

OpenStudy (anonymous):

No, it depends which interval you are using for graphing. Notice that cos(2 x) is periodic of period \(\pi\)

OpenStudy (anonymous):

1 moment, i am emailing myself the picture of my work then ill put here

OpenStudy (anonymous):

OpenStudy (anonymous):

Be careful cos(0) =1

OpenStudy (anonymous):

and not zero

OpenStudy (anonymous):

the first coordinate?

OpenStudy (anonymous):

Your graph is not right as pictured. It does not go through the origin.

OpenStudy (anonymous):

ok, what did i do wrong? my wave is the same, but shifted to the right

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=plot+2+cos%28+x%29 Here is the graph. My first graph was for cos(2x)

OpenStudy (anonymous):

did i set up my coordinate table wrong?

OpenStudy (anonymous):

that isnt the problem though, the problem is y=2cosx

OpenStudy (anonymous):

Your confusing sin and cos. cos(0) =1 and not zero

OpenStudy (anonymous):

That is why I gave you the second link

OpenStudy (anonymous):

i see the graph, but i dont see an explamation of how to get the graph

OpenStudy (anonymous):

what did i do wrong in setting up my table of coordinates?

OpenStudy (anonymous):

hey man, i figured it out. cosx=cos0=1 because trig functions of quadrantal angles

OpenStudy (anonymous):

y=2cosx 1.) Plug value in X, and solve to get Y this gets you your xy values 2.) x=0,pi/2, pi, 3pi/2 2pi this is what we plug in to get y value 3.) use the unit circle values, cos is x coordinate, sin is y coordinate(cos,sin) 4.) y=2cos(0), 2*1=2, so y=2, y=2cos(-1) at pi 2(-1)=-2, so y=-2 y=2cos (0), at pi/2 2*1=2, so y=2 y=2cos (0), at 3pi/2 2(1)=2, so y=2 y=2cos(1), at 2pi 2(1)=2, so y=2 5.) so x values= 0,pi,pi/2,2pi,3pi/2 y values= 2, -2, 2, 2, 2 Understand?

OpenStudy (anonymous):

yes sir, i understand. that sending me to a website crap doesnt help. heck, i already went to websites before posting my question, it didnt help. posting websites doesnt help. again thank you

OpenStudy (anonymous):

I agree, sorry I am a slow typer, Im glad you understand, feel free to ask me any questions!

OpenStudy (anonymous):

no problem, ill be patient for a thorough explanation anyday

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