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Calculate g(b) and g'(b), where g is the inverse of f. f(x) = x-cos(x), b = -1 g(b) = g'(b) =
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So first you need to find g(-1)
if g(-1)=k then f(k)=-1
by the rule that they are inverses
so just find for what k do we have k-cos(k)=-1
you do not have to solve
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a guessing/ trial and error method is needed
so 0
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