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x^3+2x+4=12 How can I factorize this to give me X=2 ?
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f(x) = x^3 + 2x - 8 = 0 if x = 2 is a root of this equation then f(2) = 0 but f(2) = 8+4 - 8 = 4 so 2 is not a root
r u sure the first term is x^3? - because if it's x^2 then x=2 is a root
sorry I meant x^3 +2x -12 = 0
ok then f(2) = 0 which means that x-2 is a factor you can use long division:
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