x2 - 8 -------- x + 6 and x =-2
Have you considered substitution? x+6 given x = -2 gives (-2) + 6 = 4 You do the numerator. Note: Folks in the chats are interested mostly in talking about other things, rather than helping or studying. Sorry about that. We can't seem to change that behavior.
This is your new problem once you substitute x for -2 \[\frac{ -2\times2-8 }{ -2+6 }\]
Do you think you will be able to solve that?
I believe that would be \((-2)^{2} - 8\)
Maybe, the exponent sign was not placed, but most likely your right.
If yes, this is the problem \[\frac{ -2^2-8 }{ -2+6 }\]
Just as a side note, if you are programming computers, the notation "-2^2" can be a little ambiguous. Your specific language should tell you what it means. In some, the "Unary Minus" is very high precedence and you get (-2)^2. In others, evaluation may be strictly right-to-left and you get -(2^2). In my opinion, this situation is important to clarify with parentheses. Make sure whoever is reading your work understands what you mean by -2^2. End of Side Note.
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