Question

Help
Identify the vertex and the axis of symmetry of the graph function y=3(x+2)^2-3.

V:2,-3 Axis: x=2
V:-2,-3 Axis: x=-2
V:2,3 Axis: x=2
V:-2,3 Axis:x=2

Answer 1

@kirbykirby

Answer 2

So, you have a parabola already in its vertex form: \(y=a(x-h)^2+k\)
And the vertex of the parabola is the coordinates \((h, k)\) , can you identify h and k here?

Answer 3

h=2, k=3?

Answer 4

or does k=2-3

Answer 5

Let's see if we can re-write the given equation so that it matches the format of the vertex form:
\(y=3(x-(-2))^2+(-3)\), this is equivalent to the equation you were given

Answer 6

Mhmm

Answer 7

So so, it's V:-2,-3 Axis: x=-2?

Answer 8

yes absolutely :)

Answer 9

Thanks so much. <3 ~~[*~*]~~

Answer 10

your welcome

Answer 11

That was my first guess too! Dun worry it was an educated guess.

Answer 12

=]