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A ball is kicked at a velocity of 36 m/s at an angle of 45o off the ground. How far away does the it land?

Question

Help will be rewarded.
 A ball is kicked at a velocity of 36 m/s at an angle of 45o off the ground. How far away does the it land?

loinducoeur · Answer

Okay! So, first, you split the 36m/s into a horizontal and vertical vector. After that, you find out the time of flight, using $$v=u+at$$But you have to rearrange that equation. 
After that, you have the time, so you can use $$D=s \times t$$ to get the distance.

Don't forget that you need to multiply the time by 2, because it goes up AND down.  If it's still not clear, then I can show you my workings and maybe it'll be clearer :)

anonymous · Answer

Makes sense, thank you that helps a lot.