Question

f(x)=-2(x-2)^3(x-3)^2(x+1)
find x-intercept

Answer 1

plug in f(x) = 0 and solve for x


f(x)=-2(x-2)^3(x-3)^2(x+1)

0=-2(x-2)^3(x-3)^2(x+1)

-2(x-2)^3(x-3)^2(x+1) = 0

(x-2)^3 = 0 or (x-3)^2 = 0 or x+1 = 0


I'll let you finish

Answer 2

well the (x-2)^3 is what i don't know what to do with

Answer 3

you take the cube root of both sides

Answer 4

the cube root of (x-2)^3 is simply x-2

the cube root of 0 is 0

Answer 5

after taking the cube root, you go from (x-2)^3 = 0 to x-2 = 0

Answer 6

do i foil the (x-3) for (x-3)^2 then?

Answer 7

no if (x-3)^2 = 0, then x-3 = 0

I took the square root of both sides

Answer 8

oh okay. thank you!

Answer 9

np