ok who can help me with this problem ill post the link

Question

anonymous · Answer

attachment

jim_thompson5910 · Answer

what are the instructions?

anonymous · Answer

the instructions just say to solve for A nothing more

jim_thompson5910 · Answer

solve for A? The variable A is nowhere in that problem.

anonymous · Answer

im so sorry i mixed up problems I'm supposed factor it

jim_thompson5910 · Answer

have you learned about factor by grouping?

anonymous · Answer

yes i tried that but the answer i got was marked wrong

jim_thompson5910 · Answer

show me what you have so far

anonymous · Answer

ok i can't find the work that i did for the problem all i do know is i split the problem in half and looked to see what i could take out of each half

jim_thompson5910 · Answer

ok write that out on here please

anonymous · Answer

ok the first half i did was 2qx^2+pqx the second half was -16x-p

jim_thompson5910 · Answer

you forgot an 8

anonymous · Answer

i know for the first half i can take out a 2qx

jim_thompson5910 · Answer

you can't take out 2, but you can take out qx

anonymous · Answer

yes sorry thats what i meant

anonymous · Answer

so i would have qx(2xp) and then for the second half i can take out 8 so I'm left with p-2x

jim_thompson5910 · Answer

qx(2xp) looks odd

anonymous · Answer

yeah there is another q

anonymous · Answer

so its 2qxp not 2xp

jim_thompson5910 · Answer

2qx^2+pqx would factor to qx(2x+p) 

I think that's what you meant

anonymous · Answer

yeah thats what i meant i don't know whats wrong today i can't seem to do anything right sorry

jim_thompson5910 · Answer

its ok, you're doing great

jim_thompson5910 · Answer

-16x-8p would factor to ???

anonymous · Answer

well you can take out a -8 so it would be -8(2x+p) right?

jim_thompson5910 · Answer

correct

jim_thompson5910 · Answer

let's compare the two factorizations we got

qx(2x+p) 
-8(2x+p)

jim_thompson5910 · Answer

notice how we have (2x+p) show up

anonymous · Answer

yes

jim_thompson5910 · Answer

so we can ignore those terms, and focus on the qx and -8

they form the binomial qx-8

that means the whole thing factors to (qx-8)(2x+p)

jim_thompson5910 · Answer

so I basically factored out that GCF of (2x+p) when I went from qx(2x+p) -8(2x+p) to (qx-8)(2x+p)

anonymous · Answer

yes that makes sense so the answer would be (ax-8)(2x+p)

jim_thompson5910 · Answer

q, not a

jim_thompson5910 · Answer

but yeah you have it

anonymous · Answer

yes sorry i was thinking q but a got typed

anonymous · Answer

thanks for your help

jim_thompson5910 · Answer

np