Mathematics
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OpenStudy (anonymous):
(b+9) x (b+3) explain/ check if my answer is right
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OpenStudy (anonymous):
so do i only do 9x3?
OpenStudy (anonymous):
which is 27
OpenStudy (anonymous):
no use this formula (a+b)(a+b)= a^2+2ab+b^2
OpenStudy (mayankdevnani):
no !! there is also a variable i.e b
you have to multiply this variable also
OpenStudy (anonymous):
FOIL method
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OpenStudy (anonymous):
so it would be b^2+12b+27
OpenStudy (mayankdevnani):
\[\large \bf (b+9)(b+3)=b(b+3)+9(b+3)\]
\[\large \bf b^2+3b+9b+27\]
\[\large \bf b^2+12b+27\]
OpenStudy (anonymous):
oh okay i think i get it now O.o
OpenStudy (mayankdevnani):
good :)
OpenStudy (anonymous):
so for (x+2) x (x-3) i would use the same formula @mayankdevnani
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OpenStudy (mayankdevnani):
yeah !!!
OpenStudy (mayankdevnani):
REMEMBER :-
\[\large \bf (a+b)(c+d)=a(c+d)+b(c+d)\]
OpenStudy (mayankdevnani):
@mcnabkt
OpenStudy (anonymous):
so then its x^2+ 2b-3 ugh my brain hurts like idk if i have it right so far
OpenStudy (anonymous):
@gorv
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OpenStudy (anonymous):
i just get confused with the a and b letters like idk
OpenStudy (mayankdevnani):
OpenStudy (mayankdevnani):
a,b,c,d are numbers
OpenStudy (anonymous):
well if there are only two numbers then whats c?
OpenStudy (anonymous):
and d?
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OpenStudy (mayankdevnani):
c and d are variables or numbers
OpenStudy (mayankdevnani):
and also
a and b are variable or numbers
OpenStudy (mayankdevnani):
Like in your question :-
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