What is the equation in standard form of the line which passes through (-2,-3) and has a slope of 1/2
I need help urgently
The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point (0,b). Using the slope-intercept, we can translate it to the standard form given as Ax+By=C where A, B, and C are constants. Step 2. Now we have to find the line with slope m=1/2 going through point (-2,-2). Step 3. Given two points (x1,y1) and (x2,y2), then the slope m is given as y2-y1 m= ----- x2-x1
Let (x1,y1)=(-2,-3) or x1=-2 and y1=-3. Let other point be (x2,y2)=(x,y) or x2=x and y2=y
Ok
Then what
Now we're given m=1/2 . Substituting above values and variables in the slope equation m yields the following steps: y2-y1 m= ----- x2-x1 y2-(-3) m= ----- x2-(-2)
y2-(-3) 1/2= ----- x2-(-2)
y2+3 1/2= ----- x2+2 Multiply x+2 to both sides to get rid of denominator on right side of equation.
Ok
what do you get?
X-2y=4
how did you get that?
Multiplying e sides
The answers ae 2x+y=4 2x-y=4 X+2y=4 x-2y=4
Choices
d is correct. sorry im in 3 questions right now, I forgot to fix the 1/2
Great job!
Thanks if u dont have a probkem can u help me with another
sure :)
Find the average rate of change for the given function ffrom x=-3 to x=-1 -1 -2 1 2
There is graph going through -4,0 and 0,4
ok let me work on it real quick.
Ok
first find the slope.
First find the slope of the given co-ordinates in the graph, and then make equation out of it.
@Sthalha1 do you know the slope formula?
Mx+b
the formula for finding slope
because we need slope to form a equation
slope=m=y2-y1/x2-x1 <--- you have to remember this from now on
Ok
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