Question

write the equation of a line in slope-intercept fo that is parallel to y=5x-10 and passes throught the point (9,-3) OpenStudy

Answer 1

(9,-3); y=5x-10.
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You would use point-slope equation which is y-y1=m(x-x1). Your slope will stay the same since it is parallel, in which you will plug in 5 for m (m=slope).
y-y1=5(x-x1).

Next plug in the coordinate (9,-3). The 9 will replace x1 and the -3 will replace y1.
y-(-3)=5(x-9)

Next simpliy and solve for y.
y-(-3)=5(x-9)
y+3=5x-45
-3 -3
y=5x-48.

Your answer will be y=5x-48.

Answer 2

if you were to be asked for the PERPENDICULAR rather than parallel, you would take the opposite of the slope given and flip it (the reciprocal)