Question

Let F(x)=x^2-1 and G(x)=3-x.
Find (F-G)(6)

Answer 1

Let F(x)=x^2-1 and G(x)=3-x. Find (F-G)(6)
\[F(x)=x^2-1\]
\[G(x)=3-x\]
\[F(x)-G(x)=(F-G((x)=x^2-1 -(3-x) =x^2 + x -2 \]
\[(F-G))(6)= =6^2 + 6 -2 =40 \]

Answer 2

\[
F(x)-G(x)=(F-G((x)=x^2-1 -(3-x) =x^2 -1-3+x=x^2+x-4
\]

Answer 3

\[
(F-G))(6)= =6^2 + 6 -4 =38
\]

Answer 4

@abtster

Answer 5

Yes you're right, me bad

Answer 6

Ohh this arithmetic of mine