Question

In a regular pentagon ABCDE and regular hexagon MNOPQR, 2AB = 3MN and CD + QR = 10. Which is 4BC + 5PQ?
Answer

44

42

38

33

Answer 1

well write the equations in terms of the same sides since both polygons are regular


so they can now be written and solved as simultaneous equations

2AB - 3MN = 0
AB + MN = 10

so multiply the 2nd equation by 3 and add them

2AB - 3MN = 0
3AB + 3MN = 30
---------------
5AB = 30

so bow you can solve for AB

then go and find MN...

and then realise

4BC + 5PQ = 4AB + 5PQ

hope it helps

Answer 2

oops should read 4AB + 5MN