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Calculus1 8 Online
OpenStudy (jessicawade):

can someone help me with polynomials?

OpenStudy (pratyush5):

Please post your question. :)

OpenStudy (jessicawade):

ok . one sec

OpenStudy (jessicawade):

write a polynomial function in standard form with zeros at -3,-1 and 1

OpenStudy (pratyush5):

Do you understand this statement ? If a polynomial has a zero 'a', then one of the factor is (x-a) .

OpenStudy (jessicawade):

so they would be opposite? like 3 would be -3??

OpenStudy (pratyush5):

Yes. So essentially if it has zeros at -3 , then one factor of it would be x-(-3) i.e. (x+3). Please be kind enough to tell the other two factors :)

OpenStudy (ikram002p):

here is the formula of a polynomila of given zeros let \(z_0,z_1,....z_n\) be zeroes , then \(\Huge f(x)=\prod_{i=0 }^{n} (x-z_i)\)

OpenStudy (jessicawade):

it would be 3,1,and -1?

OpenStudy (pratyush5):

You mean x+3,x+1,x-1, right ? So yes, now simply multiply these three factors to get the polynomial.

OpenStudy (jessicawade):

a: (x-3)(x-1)(x+1) B: (x+3)(x+1)(x-1) c:x^3-3x^2-x+3 d: x^3+3x^2-x-3

OpenStudy (jessicawade):

those are teh answers

OpenStudy (jessicawade):

and ok 1 sec i got -3

OpenStudy (pratyush5):

I think you are mistaking the zero and the factor. If the zero is -3, then factor is x+3. If zero is 3, then factor is x-3.

OpenStudy (jessicawade):

oh .-.

OpenStudy (jessicawade):

x+3,x+1,x-1 x-3,x-1,x+1?

OpenStudy (pratyush5):

The series which you have written above are the correct set of factors. So when you multiply - |dw:1414348822349:dw|

OpenStudy (pratyush5):

That is, x+3, x+1 and x-1 are the factors. And when you multiply the factors of a polynomial, you get the polynomial.

OpenStudy (pratyush5):

You now just need to simplify that expression. This is because standard form means - expressing the powers and all.

OpenStudy (pratyush5):

So what do you get ?

OpenStudy (jessicawade):

X^3,x,-x

OpenStudy (pratyush5):

|dw:1414349143537:dw|

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