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Can someone please explain why sin2x = sqrt 2/2 has angles of pi/4, 3pi/4, 9pi/4, 11pi/4? I don't understand where the 9pi and 11 pi are coming from.
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well there seems to be a slight mistake if \[\sin(2x) = \frac{\sqrt{2}}{2} ~~~~then~~~~~ 2x = \frac{\pi}{4}~~~or~~~ x = \frac{\pi}{8}\]
what if I gave you a different example?
but basically its because the curve repeats... based on the information it repeats over a distance of pi.... so the period is pi.. draw the cruve draw a horizontal line through y = srt(2)/2 and you'll see how many times the horizonal line intersects sin(2x) and it forms a pattern.... a rough sketch is shown below |dw:1414350994222:dw| hope it helps
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