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Use graphs and tables to find the limit and identify any vertical asymptotes of the function. limit of 1 divided by the quantity x minus 8 as x approaches 8 from the left
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\[\lim_{x \rightarrow 8^-} \frac{1}{x-8}\]
first of all does y=1/(x-8) have any vertical asymptotoes?
no it doesn't
When you have zero on bottom, you either have a hole or a vertical asymptote. This graph has no holes because their is no common factor (x-8) on top and bottom. So you have a vertical asmptote when x-8=0.
oh okay, i get that part now
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so how would i find the asmptote
By finding when the bottom is 0.
Did you read my paragraph up there? "So you have a vertical asymptote when x-8=0."
You need to solve x-8=0 for x
x = 8
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