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calc help
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@myininaya
\[\sqrt{y}=3+\sqrt{x}\]
so you did differentiate both sides?
not just one side
ohhh
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oops
\[\frac{d}{dx} \sqrt{y}=\frac{1}{2 \sqrt{y}} y'\]
@myininaya
@inkyvoyd
hmmm... I got something upside down
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Do you want to show your work so I can tell you what happened
or what should happened
i got it, i just asked my teacher, thank you(:
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