Question

Use chain rule to solve y=sin^2x

Answer 1

\[\Large\rm \sin^2x=(\sin x)^2\]It might be easier to work with in this form.

Answer 2

So... power rule to start, yes?

Answer 3

\[\Large\rm \color{royalblue}{\left[(\sin x)^2\right]'}=2(\sin x)\color{royalblue}{\left[\sin x\right]'}\]Power rule then we chain.

Answer 4

which would be
2(sinx)*(cos)?

Answer 5

Mmmm yah looks good!

Answer 6

\[\Large\rm \color{royalblue}{\left[(\sin x)^2\right]'}=2(\sin x)\color{orangered}{\left[\cos x\right]}\]

Answer 7

Thank You! :D