cos^-1 (3/8) or arccos 3/8
they are the same thing
any answers u got
yes i know they are the same thing, some people only reconize one way. i understand how to input into a calculator, but the teacher ask us to show work.
i know the answer is 1.19, but i need to show work on paper
@acal21 , you only came to say its the same problem? i assume you dont know how to show work for it either!
@ozzy22 , can you show me how to work out the problem with no calculator?
this is actually an angle difference formula for tan problem tan (A - B) = (tan A - tan B) / (1 + tan A tan B) A = cos^-1 (-3/5) ==> x = -3 and r = 5; therefore, y = 4 (from x^2 + y^2 = r^2) tan A = -4/3 B = arcsin (8/17) ==> y = 8, r = 17, and x = 15 (again, from x^2 + y^2 = r^2) tan B = 8/15 plugging into formula: tan (A - B) = (-4/3 - 8/15) / (1 + (-4/3)(8/15)) tan (A - B) = (-20/15 - 8/15) / (1 - 32/45) tan (A - B) = (-28/15) / (13/45) = (-28/15) * (45/13) = (-3*28) / 13 = -84/13 tan (A - B) = -84/13
@ozzy22 so what do you have as the final answer?
-84/13?
yes
the correct answr for this problem is 1.19
how did u get that answer POST
my book has the answers to the odd problems, it only shows the key strokes for the solution, do you want that?
yes pls
one moment, have to take pic with phone,email to laptop then upload here
K NP
@ozzy22
1.20 rounded in two places
idk man, im completely lost on this problem
oh round to 2 decimal places in instructions
yes
sorry about the first answer
no problem, im not dwelling on mistakes. just looking for a way to show work for this on paper
\[3\div8=1.199 \]
with cos-1
then round .199 witch |dw:1414380637557:dw|
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