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A=2(pi)r^2+2(pi)hr, for r
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\[A=2pir ^{2}+2pihr \]
its not easy to solve for r
you can use quadratic formula
where did you get this problem
my math homework on web assign
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i think you have a mistake. what was the original question
yeah thats a bit odd
@ganeshie8 can you take a look at this
can you post the other parts of the question
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that is all.
could be a typo
@dan815 can you look at this
@erikuh i will get ask around, im sure somebody has an idea
@rvc can you check this out
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gtg @perl
okay thankyou(: i will ask my teacher if its a typo
ya why dont u use quadratic formula
A=2PIR^2+2PIHR a=kr^2+khr 0=kr^2+khr-a \[r= \frac{-kh +/- sqrt( k^2h^2-4*k*-a)}{2k}\]
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