Question

A school choir has 80 students; 36 of them are in seventh grade. Also, 40 students in the choir are girls; 18 of them are in seventh grade. What is the probability that a student picked at random from the choir is either a girl or is in seventh grade?

Answer 1

(girls+7th grade)/80
\((40+36)/80\)
76/80
.95
move the decimal to the right 2 places
95%

Answer 2

@sleepyjess Yes I have done this but the answer choices confuse me. A.) 27/40 B.)29/40 C.)13/40 D.)33/40
None of them equal 95%

Answer 3

hmmm then maybe there is an issue with the question wording?

Answer 4

@iGreen @perl

Answer 5

Thats what i thought too

Answer 6

unless it is supposed to be 40+18 since there are 18 girls in 7th grade

Answer 7

if we do 40+36 then we are counting the girls in 7th grade twice

Answer 8

Well..it says there are only 18 girls in 7th grade..

Answer 9

40+16/80
56/80
28/40
70%

Answer 10

40 - 18 = 22.

22 + 36 = 58.

58 / 80 = 0.725 = 72.5%

Answer 11

So what's gonna be your answer? @tyler_ralston

Answer 12

40+18/80
58/80
29/40
72.5%

Answer 13

i see where i went wrong now i did 40+16 instead of 18

Answer 14

You're right @sleepyjess we counted the girls in 7th grade twice..therefore, we had to subtract them.

40 - 18 = 22 girls that aren't in 7th grade.

22 girls that aren't in 7th grade + 36 7th grade students = 58 students.

58 students / 80 total students = 72.5%

Answer 15

Yep, so your answer is 29/40. @tyler_ralston

Answer 16

THank You @iGreen and @sleepyjess

Answer 17

No problem!

Answer 18

\(\Large\cal\color{magenta}{No~problem!~Happy~to~help~\ddot\smile}\)