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@mathmath333
for size 3 number of wheels =\(4\times 2+3\times2+3\times2\) =\(20\)
Size 12 contains \(74\) wheels on it. by adding \(4\times2+11\times2\times 3=\huge 74\)
3. \(\huge\tt yes \), Mick is correct, he said it has 38 wheels because, he has \(\huge1~~ engine \) and \(\huge 5 ~~carrieges\) \(\huge8+5\times 6=38\)
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\(\huge f(n)=8+(n_1-1)\times 6\\~\\ \Large\text{where \(n_1\) = number of sets}\)(
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