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Solve x divided by negative six is less than or equal to three for x. Show your work.
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so you have \[\frac{x}{-6} \le 3\] multiply both sides of the inequality by -6 and reverse the inequality for the solution
anyone know?
you multiply -6 by itself and 3 by -6\[\frac{ x }{ -6\times-6 }=3\times-6\]
so it would be \[x \le -18\]
@mercedesbustos12
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well not quite its \[\frac{x}{-6} \times -6 \le 3 \times -6\] then reverse the inequality
and don't forget to reverse the inequality this is why using @minimissy22 \[-24 \le -18\] but is \[\frac{-24}{-6} \le 3\]
so which one is it?
@campbell_st @minimissy22
It is @campbell_st I realized I messed up sorry @mercedesbustos12
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