PLEASE HELP!!! I have a math test tomorrow and need help with substitution and elimination. 1) y=5x+3, y=x-9 2) 2x-y=5, -3x+4y=0
\(\large { (1)\ hint \begin{cases} {\color{brown}{ y}}=5x+3\\ {\color{brown}{ y}}=x-9 \\ \quad \\ {\color{brown}{ y}}={\color{brown}{ y}} \end{cases} }\) you could do the same for the (2) one
or you could just solve the 1st equation of the (2) set for "y" only and substitute on the 2nd equation of (2)
It'd be nice if you laid out the equation so could follow through it, instead of guessing and getting it wrong
@jdoe0001
That guy jdoe0001 is good. Follow his lead @Syli
elimination: move all variables to one side y=5x+3 subtract 5x y=x-9 subtract x so, y-5x=3 y-x =-9 lets eliminate y bymullt. here by -1 and then add the 2 equations together so, y-5x =3 -y+x = 9 ____________ -4x = 12 divide both by -4 x=12/-4 or - 3 plug in for x and get y y =-3-9 y=-12 do a check -12-5(-3) =3 -12+15=3 3=3 check here is substitution y=5x+3 y=x-9 since y = x-9 plug in for y in eq(1) x-9= 5x+3 add 9 both sides and subtract 5x so -4x= 12 x=-3 we already found y and did the check good luck on the test.
Thank you very much! :) @zpupster
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