Question

Solve the following system of linear equations:
x + y + 5 z = 4
x + y + 5 z = 4
There are infinitely many solutions with two arbitrary parameters.
Enter your solution below. If a variable is an arbitrary parameter in your solution, then set it equal to itself, e.g., w =w .

x =?
y =?
z = ?

Answer 1

what u think?

Answer 2

I have no idea how to do this problem at all. I don't even know why there are two arbitrary parameters.

Answer 3

here there are 2 equations and 3 variables
principle says "there must be n number of equations for n variables"

Answer 4

there must be n number of equations for n variables to solve n variables

Answer 5

How do I solve for x,y, and z then? I don't understand

Answer 6

do u have options here

Answer 7

Options for what?

Answer 8

I have to enter the answer myself

Answer 9

ex this
https://answers.yahoo.com/question/index?qid=20090130133749AAdgdHk

Answer 10

y=y and z=z, but what is x?

Answer 11

all three are variables

Answer 12

x isn't arbitrary, so I don't know what value to give it that isn't just "x"

Answer 13

so are y and z

Answer 14

y an z are arbitrary, which is why y=y and z=z

Answer 15

x does not equal x

Answer 16

arbitrary means constant in maths

in the equation arbitrary parameters are 4 and 5

Answer 17

what?

Answer 18

If a variable is an arbitrary parameter in your solution, then set it equal to itself, e.g., w =w .

Answer 19

one possible solution for
should be here
\(x=-7,y=1,z=2\)


so z is not changing here

Answer 20

x does not equal -7