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limit question as x approaches sqrt(x^2+1) find the limit
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as x approaches 3? 0? \(\infty)?
as x approaches infinity
sqrt(x^2+1)
as x gets larger, so does \(\sqrt{x^2+1}\)
so \(\infty\)
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so the answer is just infinity?
of course \(x\) gets bigger, \(x^2+1\) gets bigger, \(\sqrt{x^2+1}\) gets bigger think of what the graph looks like after a while it just looks like the line \(y=x\)
hmmm thanks
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