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Mathematics 19 Online
OpenStudy (jessicawade):

binomial expansion help!!!

OpenStudy (jessicawade):

the term 35x^3y^4 is term in which binomial expansion

jimthompson5910 (jim_thompson5910):

list out your choices

OpenStudy (jessicawade):

ok

OpenStudy (jessicawade):

a. (x+y)^12 b. (x+y)^6 c. (7x+5y)^7 d.(x+y)^7

jimthompson5910 (jim_thompson5910):

ok I see what they want

jimthompson5910 (jim_thompson5910):

notice the exponents for 35x^3y^4 are 3 and 4

jimthompson5910 (jim_thompson5910):

the exponents add to 3+4 = 7 so the degree of this polynomial is 7

OpenStudy (jessicawade):

yes

jimthompson5910 (jim_thompson5910):

meaning that the overall outer exponent has to be a 7

OpenStudy (jessicawade):

oh.

jimthompson5910 (jim_thompson5910):

so the answer is either c. (7x+5y)^7 or d.(x+y)^7

OpenStudy (jessicawade):

yes. im wondering if it is c because 7x5 is 35

jimthompson5910 (jim_thompson5910):

do you have pascals triangle with you?

OpenStudy (jessicawade):

no should i print one out? thats probably why i am confused they ddint have it in my lesson

jimthompson5910 (jim_thompson5910):

http://mathforum.org/workshops/usi/pascal/images/pascal.hex2.gif

jimthompson5910 (jim_thompson5910):

look in the row that starts with 1, 7, etc

jimthompson5910 (jim_thompson5910):

35x^3y^4 is the 4th term what is the fourth number in that row?

OpenStudy (jessicawade):

ok

OpenStudy (jessicawade):

35

jimthompson5910 (jim_thompson5910):

what is the fourth number in the row 1, 7, ....

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

so if the answer was choice C, then we'd have 35*(7x)^3*(5y)^4 = 7,503,125x^3y^4 that result is way too big

jimthompson5910 (jim_thompson5910):

choice C is out

OpenStudy (jessicawade):

so its D?

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (jessicawade):

wow. lol that was pretty easy

jimthompson5910 (jim_thompson5910):

yeah it's easier with the triangle

OpenStudy (jessicawade):

like the z-scores haha

OpenStudy (jessicawade):

thansk :)

jimthompson5910 (jim_thompson5910):

you're welcome

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