Question

*WILL GIVE MEDAL* Can someone help me find the parabola of f(x)=2(x-6)^2+4

Answer 1

I already have it graphed, I think I need the points.

Answer 2

f(x)=2(x-6)^2+4
mix at f'(x) = 0
f'(x) =4(x-6) = 0, so x = 6
and y = f(6) = 4

thus the minimum is (6,4)

Answer 3

what other points do you need?

Answer 4

oh, and mix is a typo, I meant min

Answer 5

@Sherabartlett
is it just the minimum? Or do you need other points as well?