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Solve the absolute value inequality: |2x + 3| > 27 A) -12 < x < 12 B) x < -15 OR x > 12 C) x > 15 OR x < 15 D) -15 < x < 15
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i think it's C
Our two equations are gonna be: 2x + 3 > 27 and -2x - 3 > 27 --------------- 2x + 3 > 27 Subtract 3 to both sides: 2x > 24 Divide 2 to both sides: x > 12 --------------- -2x - 3 > 27 Ad 3 to both sides: -2x > 30 Divide -2 to both sides: Can you divide 30 / -2? @pigglet
-15
Yep, that gives us x < -15, we have to switch the sign because we're dividing by a negative number.
So our solutions are: x > 12 and x < -15
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