Question

Help to convert to standard equation?
o f(x) = x^2 + 6x – 16
o g(x) = x^2 +6x + 1

Answer 1

@iGreen @ganeshie8

Answer 2

So far i have:
1. To open these doors, you must match the number and type of solutions for the following two functions in standard form.
o f(x) = x2 + 6x – 16
x^2 + 8x – 2x – 16
(x – 8)-2(x-8)
(x+8)(x-2)
So the solutions would be -8 and 2.
o g(x) = x2 +6x + 1
x^2 + x8 – 2x + 1
x(x + 8) -2x + 1
So the solutions are -8 and 2.
Is it correct?

Answer 3

@Yahoo! @YanaSidlinskiy @midhun.madhu1987 ?

Answer 4

That's what I got.

Answer 5

so it would be
(6)^2-4(1)(16) Simplify that

Answer 6

f(x) is fine..

but g(x) cant be simplified this way... you need use Quadratic Formula .. i guess...

Answer 7

Can you help me with it lel? i kinda suck at these things ._.

Answer 8

\(y = ax^2 + bx + c\)
We all suck at it!!

Answer 9

@undeadknight26 it would be -8 right?.

Answer 10

*-28

Answer 11

i take tht back it 64

Answer 12

o g(x) = x2 +6x + 1
x^2 + 8x - 2x + 1
x(x + 8)(x + 2) + 1

Answer 13

so then it would be 36+64 which would be 100

Answer 14

I just need to put it into standard ._.
I dunno what im doing ._.

Answer 15

Is the question completely written above?

Answer 16

o g(x) = x^2 +6x + 1
This is the G(x) equation.

Answer 17

I mean... is the question this much??
Help to convert to standard equation?
or anything else is there?

Answer 18

Well there are other parts but for now i just need help with this one.

Answer 19

http://www.mathwarehouse.com/geometry/parabola/standard-to-vertex-form.php

standard form of parabola is ax^2+bx+c
vertex stand form is
y=a(x-h)^2 + k

Answer 20

your equations are in standard form

Answer 21

They are?

Answer 22

g(x) = x2 +6x + 1
x^2 + 8x - 2x + 1
x(x + 8)(x + 2) + 1
(x+8)(x+2)
Are u sure its correct?

Answer 23

you can put them in vertex form

complete the square and add the constants together

follow the link i gave

Answer 24

I just need to put them in standard form for now ._.
I ask again ._.
Is it correct?!