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OpenStudy (anonymous):
four less than twice the smaller number of two consecutive odd integers is eleven more than the larger odd integers i'm having trouble setting it up
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OpenStudy (studygurl14):
"two consecutive odd integers"
x and x + 2
"twice the small number"
2x
"4 less"
2x - 4
"is"
2x - 4 =
"larger interger"
x + 2
"eleven more"
x + 2 + 11
So...
2x - 4 = x + 2 + 11
OpenStudy (anonymous):
when i find the answer do i have to plug it in 2 find the other integer?
OpenStudy (studygurl14):
when you find x, solve "x + 2" to find the second one
OpenStudy (anonymous):
do i add 11 to the equation or not?
OpenStudy (studygurl14):
I don't understand what you mean...
This is the equation to solve
2x - 4 = x + 2 + 11
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OpenStudy (anonymous):
do i plug the answer to "x+2+11" or just "x+2"
OpenStudy (studygurl14):
just into "x+2"
OpenStudy (anonymous):
so the answer will be 19?
OpenStudy (anonymous):
thank you so much btw
OpenStudy (studygurl14):
The larger number would be 19, correct.
You're welcome.
Can I have a medal please?
(click best answer)
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OpenStudy (anonymous):
done and thank you again how do i find the smaller number?
OpenStudy (studygurl14):
The smaller number would be 19 - 2, which is 17
OpenStudy (anonymous):
okay thank so much
OpenStudy (studygurl14):
yw
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