four less than twice the smaller number of two consecutive odd integers is eleven more than the larger odd integers i'm having trouble setting it up
"two consecutive odd integers" x and x + 2 "twice the small number" 2x "4 less" 2x - 4 "is" 2x - 4 = "larger interger" x + 2 "eleven more" x + 2 + 11 So... 2x - 4 = x + 2 + 11
when i find the answer do i have to plug it in 2 find the other integer?
when you find x, solve "x + 2" to find the second one
do i add 11 to the equation or not?
I don't understand what you mean... This is the equation to solve 2x - 4 = x + 2 + 11
do i plug the answer to "x+2+11" or just "x+2"
just into "x+2"
so the answer will be 19?
thank you so much btw
The larger number would be 19, correct. You're welcome. Can I have a medal please? (click best answer)
done and thank you again how do i find the smaller number?
The smaller number would be 19 - 2, which is 17
okay thank so much
yw
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