Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

can any one help Solve x divided by negative six is greater than three for x. x is greater than negative eighteen x is less than negative two x is less than negative eighteen x is greater than negative two

OpenStudy (anonymous):

Well lets do it here. x−6>3=−x6>3 To simplify, isolate x first. Remember, dividing both sides by a negative number flips the inequality sign.

OpenStudy (anonymous):

Ok the = sign in between is not practical :) I meant the inequality on the left is equal to the inequality on the right

OpenStudy (anonymous):

Lets do it in two steps. First, multiply both sides by 6: −x6>3

OpenStudy (anonymous):

Now, x is not nicely isolated yet, as it has a minus sign in front of it. Multiplying both sides by -1 is the logical next step. Remember though, multiplying both sides by a negative number flips the > sign.

OpenStudy (anonymous):

Could you continue from −x>18?

OpenStudy (anonymous):

Or is it clear? :)

OpenStudy (anonymous):

is the 18 a negative

OpenStudy (anonymous):

I think you made it way more complicated than it really was supposed to be brandon...

OpenStudy (anonymous):

I dont like giving answers but math that leads to the answers

OpenStudy (anonymous):

That does make sense but some of what you said didn't make sense and made me confused

OpenStudy (anonymous):

@BrAnDoN_AAS you made this very complicated

OpenStudy (anonymous):

sorry copied and pasted from a post with the same quetion from like a year ago

OpenStudy (anonymous):

and confusing

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

that made no sense

OpenStudy (anonymous):

i got it

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!