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Two objects are moving along separate linear paths where each path is described by position, d, and time, t. The variable d is measured in meters, and the variable t is measured in seconds. The equation describing the graph of the position of the first object with respect to time is d = 2.5t + 2.2. The graph of the position of the second object is a parallel line passing through (t = 0, d = 1). What is the equation of the second graph?
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A linear equation is written is this form: \(y = mx + b\) If both lines are parallel, then they have the same slope \(m\). In order to find \(b\) you can used they point the gave you and plug them where \(y\) and \(x\) are (i.e, solve for \(b\)). Here d is y and t is x.
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