Question

HELP ILL DO ANYTHING - - ---- Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6). (2 points)

y = 1 over 3 x + 7
y = -3x + 3
y = 1 over 3 x + 3
y = -3x + 7

Answer 1

\[y-6=3(x+1)\] is a start

Answer 2

yes sir

Answer 3

solve for \(y\) and you are done

Answer 4

@satellite73 i need your help still im stupid

Answer 5

@satellite73 pleaseeeeeee im in a rush

Answer 6

help :(

Answer 7

Since the slope of parallel lines has to be the same you can do
y=-3x+b.
Then plug in the point you are given and solve for b to find the y intecept

Answer 8

ok can you help with that because im really dumb

Answer 9

and explain

Answer 10

you there?

Answer 11

y=-3x+b
plug in the give point (-1,6). Since ordered pairs are in (x,y) form -1=x and 6=y
6=-3(-1)+b
Then solve for b
6=3+b
subtract 3 from both sides and you get
3=b.

Since the slope of the parallel line is the same your parallel equation is
y=-3x+3

Answer 12

i apologize but im in a rush :(

Answer 13

wait

Answer 14

can you help me with a few more?

Answer 15

i can try

Answer 16

Write the equation of the line that is perpendicular to the line y = 3 over 2x + 4 and passes through the point (-6, 3). (2 points)

y = 3 over 2x - 1
y = 3 over 2x + 3
y = - 2 over 3x - 1
y = - 2 over 3x + 3

Answer 17

can you guide me step by step?

Answer 18

??

Answer 19

yeah just a sec

Answer 20

ok if i dont answer that means i need a sec need to get a beverage'

Answer 21

sorry about that im back!

Answer 22

Is this your equation
or is it this