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OpenStudy (anonymous):
What is the equation of the graphed line?
OpenStudy (anonymous):
from the graph, pick two points that we can work on
OpenStudy (anonymous):
0,0 and 3, 2 @Data_LG2
OpenStudy (anonymous):
wait, wouldn't it be y1-y2/x1-x2?
OpenStudy (anonymous):
ok good :)
now apply the slope formula: \(\sf \Large slope=\frac{y_2-y_1}{x_2-x_1}\)
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OpenStudy (anonymous):
yes that's right!
OpenStudy (anonymous):
okay 0-2/0-3
-2/-3?
OpenStudy (anonymous):
that's right but since the numerator and the denominator is both negative.. you can simplify it so it will only be 2/3
OpenStudy (anonymous):
okay thanks.
OpenStudy (anonymous):
no prob :)
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OpenStudy (anonymous):
but, that's correct right?
OpenStudy (anonymous):
yes, but it is better to simplify it to 2/3 to make sure
OpenStudy (anonymous):
because..this is an assessment..and I can't get a lot wrong otherwise I fail it.
OpenStudy (anonymous):
you know that we are not allowed to help if this is kind of a quiz/test/exam right? 'coz this is considered cheating.. but you did some work so it's okay ^_^
2/3 is right. blame me if it is not right :)