Question

Can someone help me with these practice problems? I give medals. Thx

Answer 1

@satellite73 @e.mccormick @perl

Answer 2

degrees and minutes? yikes
in any case the
\[\sin(70.083)=\frac{30}{x}\]

Answer 3

so
\[x=\frac{30}{\sin(70.083)}\] these minute are real annoying

Answer 4

That's what I was thinking, but I was confused by the 5'

Answer 5

second one is the same, except use cosine

Answer 6

\(5' = \frac{5}{60}\)

Answer 7

Would 31.9 be right (rounded)?

Answer 8

i don't know i didn't do it, but i could check
seems not right though

Answer 9

Hey, could you check this and tell me if I'm right?

Answer 10

http://www.wolframalpha.com/input/?i=30%2Fsin%2870.083%29

Answer 11

\[\cos(54)=\frac{h}{17}\] is where you start

Answer 12

oops that should be 27

Answer 13

\[\cos(54)=\frac{h}{27}\]so
\[h=\frac{27}{\cos(54)}\] but i am not getting the answers you have

Answer 14

That is really odd. I just did it again, and it came out to 31.9085427...