Don't understand how to do this problem, i tried solving it and got A for an answer and my teacher said it was wrong...help please
Hey @satellite73 or @perl do you know how to answer this question?
what do you have so far?
first take the derivative
f ' (x) = 2ax + b
Well i had that a=1 and b=1 so them added together would equal 2, but i did not find the derivative of f(x)....that might be whats wrong
y = x + 4 tangent to y = ax^2 + bx it's slope at x = 2, y = 6 is y'(2) = 2ax + b = 4a + b is tangent to the line x+4, which has slope 1 tangent to that means slope -1 so y'(2) = 4a + b = -1 and we also have that (2,6) is on the parabola: 4a + 2b = 6, that is 2a + b = 3 so we have to solve 4a + b = -1 2a + b = 3 so 2a = -4 a = -2 2a + b = 3 => -4+b =3, so b = 7 a + b = 5
y = x + 4 is tangent to f(x) at the point (2,6) the 'slope' of the tangent line is 1 . therefore f ' (2) = 1
looks like abster got it :)
he is fast
isn't that parallel instead of tangent?
ok....@abtster 5 is not an answer choice
the curve y = x + 4 is tangent to f(x)
yeh so f'(2) = -1
so what would a+b=?
5
5 is not an answer choice
The question is wrong
My teacher got an answer
let me try
ok
ok....
if parallel was meant then we have 4a+2b = 6 or 2a +b =3 4a+b =1 (if x+4 is parallel) then 2a = -2 a = -1 and back subst -2 +b = 3 b = 5 a + b = 4 is one of the anwers: D
f ' (2) = 1 f(2) = 6 4a + b = 1 4a + 2b = 6
I got b = 5 , and a = -1
a + b = 4
ok awesome, so you both got 4
x+4 is parallel of cource that is tangent stupid me
yeah i plugged into f ' (x) incorrectly, but it works now
ok, i get it now. Thank you both for your help!!
just given you your deserved medal, perl
thanks abtster :)
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