Solve the system by elimination.
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
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OpenStudy (anonymous):
@StudyGurl14 by any chance do you know this?
OpenStudy (studygurl14):
Ooh...yuck. I know how, but I really hate systems of equations with three variables...
OpenStudy (studygurl14):
Okay, so do you know what it means by "elimination"?
OpenStudy (anonymous):
Im guessing I have to eliminate variables or numbers or something?
OpenStudy (studygurl14):
sorta.
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OpenStudy (studygurl14):
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
OpenStudy (anonymous):
Okay, what does it mean?
OpenStudy (studygurl14):
Okay, notice how all the equations start with either 2x or -2x?
OpenStudy (studygurl14):
It is easier to show you, rather than tell you
OpenStudy (anonymous):
yes I see
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OpenStudy (studygurl14):
You can eliminate the x variables of the equations by adding/subtracting the equations from each other.
take the first equation and the third equation
-2x+2y+3z=0
2x+3y+3z=5
______________
0 + 5y + 6 z = 5
OpenStudy (anonymous):
okay so do that with them all? like 1,2 then 1,3 then 2,3?
OpenStudy (studygurl14):
And then, you can do the same with the first two equations
-2x-y+z=-3
multiply by -1
2x + y - z = 3
Next,
-2x+2y+3z=0
2x + y - z = 3
_______________
0 + 3y + 2z = 3
OpenStudy (anonymous):
what do i do after that?
OpenStudy (studygurl14):
Now you have these two equations:
5y + 6z = 5
3y + 2z = 3
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OpenStudy (studygurl14):
You want to eliminate one more variable so you can solve for the other variable.
OpenStudy (anonymous):
okay..
OpenStudy (studygurl14):
3y + 2z = 3
multiply by -3
-9y - 6z = -9
See how it is changed?
OpenStudy (anonymous):
yes but why multiply by -3? and what would multiply the 5y + 6z = 5 by would it be -5?
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OpenStudy (studygurl14):
I multiplied it by -3 so that the 2z would change to -6z, which, when added to the 6z from the other equation, equals zero. Make sense?
OpenStudy (anonymous):
yes! So only one equation needs that not both?
OpenStudy (studygurl14):
right. in some cases, you might need to multiply both equations by something, but not in this case
OpenStudy (studygurl14):
So, you have
-4y = -4
What does y = ?
OpenStudy (anonymous):
Oh okay..
oh um.. lol uhhh -4?
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OpenStudy (studygurl14):
Divide both sides by -4. What is -4/-4?
OpenStudy (anonymous):
1?
OpenStudy (studygurl14):
Correct! So...y = 1
OpenStudy (anonymous):
thats it? or is there more?
OpenStudy (studygurl14):
There's more...lol. You still have to find the values for x and z
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OpenStudy (anonymous):
oh lol darn it.... how do i do that?
OpenStudy (studygurl14):
Okay, so we have this equation from before:
5y + 6z = 5
Now that we know y =1, how do we solve for z?
OpenStudy (anonymous):
Im not sure..
OpenStudy (anonymous):
maybe do the same thing or something similar?
OpenStudy (studygurl14):
Plug in 1 for y, and solve for z
5(1) + 6z = 5
5 + 6z = 5
6z = 0
z = ?
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OpenStudy (anonymous):
would it be 6 divided by 6?
OpenStudy (anonymous):
1?
OpenStudy (studygurl14):
Nope. Hint: Any number times 0 = 0
OpenStudy (anonymous):
oh 6 x 0? so 0?
OpenStudy (studygurl14):
Correct. So z = 0
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OpenStudy (studygurl14):
So we know z = 0, and y = 1. How do we find the value of x?
OpenStudy (anonymous):
would we use multiplication again?
OpenStudy (studygurl14):
we would plug in again.
OpenStudy (anonymous):
using multiplication?
OpenStudy (studygurl14):
Let's use the very first original equation.
-2x+2y+3z=0
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OpenStudy (studygurl14):
If z = 0, and y= 1, how would we find x? Using this equation ^
OpenStudy (anonymous):
plug it in: -2(1)+2y+3(0)=0 ?
OpenStudy (studygurl14):
Close. We don't know the value of x yet. We know y = 1, so you would replace y with 1, not x
OpenStudy (anonymous):
Oh i mean -2x+2y(1)+3(0)=0 haha sorry
OpenStudy (anonymous):
Yeah I mistyped lol
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OpenStudy (studygurl14):
Right!
OpenStudy (studygurl14):
Okay, so you have:
-2x+2(1)+3(0)=0
What now?
OpenStudy (anonymous):
man.. um.. i think like this?
-2x+2(1)+3(0)=0
-2x+2+3=0
after that Im a bit stuck but i am starting to understand!
OpenStudy (anonymous):
@StudyGurl14
OpenStudy (anonymous):
lol 5!
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OpenStudy (studygurl14):
actually..no
OpenStudy (studygurl14):
3(0) = ?
OpenStudy (anonymous):
3? lol unsure now :P
OpenStudy (studygurl14):
Remember this rule. Whenever a number is being multiplied by 0, the result is 0. Whenever a number (except for 0) is being multiplied by 1, the answer is that number. So, in this situation, is 3 being multiplied by 1 or 0?
OpenStudy (anonymous):
oh sorry the answer is 0 wow im dumb
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OpenStudy (studygurl14):
Yep. And no you're not. It is easy to forget the simple stuff once you start dealing with super hard stuff that occupies all the space in your brian..lol
OpenStudy (studygurl14):
Okay, so back to
-2x+2(1)+3(0)=0
This would simplify to...
-2x + 2 + 0 = 0
What's the next step?
OpenStudy (anonymous):
lol yeah my "brian" hurts right now hahaahah :P
OpenStudy (studygurl14):
lol.
OpenStudy (anonymous):
-2x + 2?
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OpenStudy (studygurl14):
Yep...I named my brain Brian. lol
OpenStudy (studygurl14):
Yep
-2x + 2 = 0
What now?
OpenStudy (anonymous):
HAHA!! Wait how does 2x + 2 equal zero? :/
OpenStudy (anonymous):
@StudyGurl14 ? :(
OpenStudy (studygurl14):
Because. That was the original equation...go back a few posts and look. You can't eliminate the equals sign...or the zero on the other side. Only the one zero on the left side of the = sign
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OpenStudy (anonymous):
oh okay so what would be the next step?
OpenStudy (anonymous):
@StudyGurl14 why do you keep leaving meee we are almost done!!
OpenStudy (studygurl14):
sorry i have to check on my own quesiton
OpenStudy (studygurl14):
ok. so next step...
OpenStudy (anonymous):
oh I thought you were mad at me lol
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OpenStudy (studygurl14):
-2x + 2 = 0
- 2 -2
_______________
-2x = -2
What does x equal?
And of course I'm not mad at you.
OpenStudy (anonymous):
4? lol thank god i need you!
OpenStudy (studygurl14):
Nope....
Divide both sides by -2
What is -2/-2?
OpenStudy (anonymous):
oh i multiplied!
its 1 :)
OpenStudy (anonymous):
@StudyGurl14
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OpenStudy (studygurl14):
correct
OpenStudy (studygurl14):
So....
x = 1
y = 1
z = 0
OpenStudy (anonymous):
So what do i do with those? am I done or do I need to do something else? @StudyGurl14
OpenStudy (studygurl14):
You're done
OpenStudy (studygurl14):
or should I say "I'm done" lol, jk. xD
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OpenStudy (anonymous):
No you should you helped so much thanks again Einstein!! :D
OpenStudy (studygurl14):
lol, you're welcome.
OpenStudy (studygurl14):
Hey, have you written me a fan testimonial yet? *hint hint*
lol, xD
OpenStudy (anonymous):
No way I thought I did!
OpenStudy (studygurl14):
sometimes it glitches. maybe try again?
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OpenStudy (anonymous):
Yeah I refreshed.. so weird this will be my third time writing it!!
OpenStudy (anonymous):
I wrote one :)
OpenStudy (studygurl14):
Thanks so much!
OpenStudy (studygurl14):
what you wrote was so nice :)
OpenStudy (anonymous):
Of course I really value your help!!! hey for the first and third equation did you divide to get 0 + 3y + 2z = 3 @StudyGurl14
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OpenStudy (studygurl14):
no I added
OpenStudy (anonymous):
added them and the other two to get the final two equations?