Please help! I need to use the chain rule to solve this problem.

Question

softballgirl372015 · Answer

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anonymous · Answer

derivative , right ?

softballgirl372015 · Answer

Yup!

anonymous · Answer

4sin^3x sec^2(4x) + tan4x 3sin^2x cos x

softballgirl372015 · Answer

Oh! I didn't know that you could use the product rule for this problem. Thanks!! :)

anonymous · Answer

They both have "x" with them so product rule applies here along with the chain rule. like sin^3x

softballgirl372015 · Answer

Okay. I understand it now. Thanks so much for your help! :)

zale101 · Answer

Use the product rule which states 
$$(uv)' = vu' + uv' $$
then when you take the derivative of sin^3x you'll get (3sin^2x)*(cosx) you'll do the chain rule where you have to take the derivative of the outer and then multiply it by the inner derivative. Same goes to tan 4x, you take the derivative of the outer sec^2 4x and multiply it by the derivative of 4x which is 4. (sec^2 4x) *(4)

anonymous · Answer

You are welcome. @Softballgirl372015