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**MEDAL** Can somebody please explain this to me?
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since 6 is half of 12, AB is half of 4
The polygons are similar, we can set up a proportion to find the missing side. \(\huge \frac{GH}{CD}=\frac{FE}{AB}=\frac{12}{4}=\frac{6}{x}\)
@satellite73 by that logic 5 is half of 9?
Im sure they dont have a fraction on the bigger FG
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5 corresponds to FG
what?
Soo, the answer is C. 3 then?
half of 4 is 3
sigh
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Oh wait, I did the wrong calculations. I used 9 instead of 6. So B. 2. Lol
been like this since early september
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