so when I throw the ball up and it hits the ground again, what will the value of H be?
OpenStudy (wmj259):
So you are looking at what values of t(time) make h=0.
So if you notice ax^2+bx+c
OpenStudy (wmj259):
You have experience with the quadratic equation?
OpenStudy (anonymous):
Quadratic equations? More or less. I barely remember, unfortunately.
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OpenStudy (campbell_st):
all you need to do is set the equation to zero and solve for t
remember h = height
so if h = 0 the ball is on the ground
so its
\[0 = -16t(t - 4)\]
hope it helps
you will have 2 values for t
t = 0 is the initial height.
so for the other t value