Question

Can anyone help me with this problem?
log(base 6) 12- log (base 6) 2=???

Answer 1

it equals 1, but i dont know how thats the asnwer

Answer 2

you start off using rule #2

http://www.purplemath.com/modules/logrules.htm

Answer 3

after that, you'll use the rule

\[\Large \log_{b}(b) = 1\]

Answer 4

so would you dividde 12 by 2? like log (12/2)???

Answer 5

correct

Answer 6

you'll then get

\[\Large \log_{6}(6) = 1\]

Answer 7

the first equation I wrote was in general for any value of b (but b cannot be 0, it can't be negative, and it can't be equal to 1)

Answer 8

ohhh okay thank you!!

Answer 9

np