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OpenStudy (anonymous):
what that 2 is suppose to be a 2y
OpenStudy (anonymous):
wait*
Nnesha (nnesha):
can be or cannot
OpenStudy (anonymous):
can
Nnesha (nnesha):
ohh sorry i thought you asking that question to us
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OpenStudy (anonymous):
so first you want to get your "y's" to the same side so subtract 2y from both sides and it will cancel out on one side and then 9-2=7 so it would be 7y+4=25 then subtract 4 from each side and it cancels out on one side and then 25-4=21 so then you would have 7y=21, now you divide 7 from both sides and 7 cancels out on one side and the 21 divided by 7= 3 so y=3
OpenStudy (anonymous):
hope it helped.
Nnesha (nnesha):
first you have to subtract 2y both side
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i subtract 2y from they 9y as well right?
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OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
soo 7y+4=25
OpenStudy (anonymous):
no...
OpenStudy (anonymous):
what i do wrong
Nnesha (nnesha):
now subtract 4 both side
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OpenStudy (anonymous):
ooo ok
Nnesha (nnesha):
7y +4 = 25 is right
OpenStudy (anonymous):
sorry i read it wrong, yes 7y+4=25 is correct
OpenStudy (anonymous):
i got 3y=25 ... now do i divide
Nnesha (nnesha):
subtract 4 on right side too
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Nnesha (nnesha):
whenever you add or subtract multiply or divide one side also have to do on other side
OpenStudy (anonymous):
3y=21
Nnesha (nnesha):
now divide by 3 both side
OpenStudy (anonymous):
y=21
Nnesha (nnesha):
always divide both side
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