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y=e^-2x+10 in the form y=Af(B(x-h))+k
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\[\large y = e^{-2x}+10\] like this ?
yep
\[\large y = 1\cdot e^{-2(x-0)}+10\]
compare it with \[\large y = A\cdot f(B(x-h))+k\]
so then A= 1, B=-2, h=0, k=10
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looks good, you should also explain how those variables affect the parent function
thank you!
h = 0, so no horizontal shift
what does k=10 tell you ?
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