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Consider the solid consisting of the first octant portion of a sphere of radius 4, centered at the origin, and lying below the plane z=2. find the volume of this solid as a triple integral.
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try \[\dfrac{1}{8} \frac{4}{3}\pi 4^3 - \iiint 1. dV\]
can we do this without volume formula, only with triple integral?
@ikram002p
could you also please express the whole integral with boundaries?
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logout close ur browser login from other account xD
you can only type boundaries and integrate, can you? @beccaboo022a
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