Will fan and medal.. 5 questions i'm stuck on.. Help please.. Solve the equation for y. 8x – 9y = 11
@mathmath333 @johnweldon1993 Help please??
D
Thank you!
@kaydra14 Help me please??
a and c
Thank youu!!
\(\large\tt \begin{align} \color{black}{7x-5y=28\\~\\ (1.)7x-5y\\ =7\times (-6)-5\times (-14)\\ =-42+70\\ =28~~~\checkmark\\~\\ (2.)7x-5y\\ =7\times (-1)-5\times (-7)\\ =-7+35\\ =28~~~\checkmark\\~\\ (3.)7x-5y\\ =7\times 4-5\times 10\\ =28-50\\ =-22~~~\wrong\\~\\ (4.)7x-5y\\ =7\times 7-5times 9\\ =49-45\\ =4~~~\wrong}\end{align}\)
@mathmath333 so it's A&B?
yes
There's 2 more after this one, I failed the test, attempting to do the last three on my own haha.
try to put that two options in RHS of equation and see if it equals 11 if so then which ever option equals 11 is correct
*LHS of equation
Alright, thanks.
u got the answer
@mathmath333 yeah it was A, i forgot i could put the question on BlackBoard so my teacher could help haha. There's one more. Then I'll be finished for the day. Yay! haha.
That's the last one.
\(\Large3x-\dfrac{y}{4}=11\) now lets put first option\(\Large(3,-8)\) \(\Large3x-\dfrac{y}{4}=11\\ \Large 3\times 3-(\dfrac{-8}{4})\\ \Large=9-(-2)\\ \Large =9+2\\ \Large =11\) \(\Large3x-\dfrac{y}{4}=11\) now lets put second option\(\Large(4,4)\) \(\Large3x-\dfrac{y}{4}=11\\ \Large 3\times 4-(\dfrac{4}{4})\\ \Large=12-(1)\\ \Large =11\\ \) so second option is also correct that means option \(\Large D\) both are solutions is correct
So B&D.. Thank you!
lol not B and D only \(\Huge D\)
Ohhhhhhhhhh haha thank you
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