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Mathematics 12 Online
OpenStudy (anonymous):

MEDAL how would you graph Y = (-2/3)x + 400 ??

OpenStudy (shinalcantara):

since you already have the y-intercept as (0,400), all you have to do is to find the x-intercept using the equation of the line taking y=0

OpenStudy (shinalcantara):

what's your x-intercept then?

OpenStudy (anonymous):

x = 600

OpenStudy (shinalcantara):

so you'll have the point as (0,400) and (600,0) you can now plot

OpenStudy (shinalcantara):

|dw:1415032143400:dw|

OpenStudy (anonymous):

okay @shinalcantara , but it says use the slope-intercept method. how would i do that ?

OpenStudy (shinalcantara):

Y = (-2/3)x + 400 have you remembered slope-intercept form?

OpenStudy (anonymous):

is it Y = mx + b ?

OpenStudy (shinalcantara):

isn't it that the form is y = mx + b where m is the slope and b is the y-intercept

OpenStudy (shinalcantara):

using that idea you will know that the y-intercept, b, is 400. then you can say that the first point is (0,400)

OpenStudy (anonymous):

okay, so what next ?

OpenStudy (shinalcantara):

since you know that the slope is -2/3 then you'll have it as |dw:1415033986388:dw|

OpenStudy (anonymous):

ohhhhh thank you!

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