MEDAL how would you graph Y = (-2/3)x + 400 ??
since you already have the y-intercept as (0,400), all you have to do is to find the x-intercept using the equation of the line taking y=0
what's your x-intercept then?
x = 600
so you'll have the point as (0,400) and (600,0) you can now plot
|dw:1415032143400:dw|
okay @shinalcantara , but it says use the slope-intercept method. how would i do that ?
Y = (-2/3)x + 400 have you remembered slope-intercept form?
is it Y = mx + b ?
isn't it that the form is y = mx + b where m is the slope and b is the y-intercept
using that idea you will know that the y-intercept, b, is 400. then you can say that the first point is (0,400)
okay, so what next ?
since you know that the slope is -2/3 then you'll have it as |dw:1415033986388:dw|
ohhhhh thank you!
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