Question

Tough math problem :(

Answer 1

What is the simplified form of x plus 1 over x squared plus x minus 6 ÷ x squared plus 5x plus 4 over x plus 4

Answer 2

\[\frac{ x+1 }{ x^2+x-6 }\div \frac{ x^2+5x+4 }{ x+4}\]

Answer 3

is this your Q ??

Answer 4

\[\frac{ x+1 }{ x^2+x-6 }\div \frac{ x^2+5x+4 }{ x+4 }\]

Answer 5

Yes! :)

Answer 6

ok so we can change division sign by multipliction and reverse the thing on right agree??

Answer 7

Agreed

Answer 8

\[\frac{ x +1}{ x^2+x-6}*\frac{ x+4 }{ x^2+5x+4 }\]

Answer 9

now first solve left term

Answer 10

denominator x^2+x-6
can u split x such that product =-6

Answer 11

yes into -3 right?

Answer 12

no lol 3 and -2

Answer 13

x^2+3x-2x-6

Answer 14

ohhh haha ok

Answer 15

can u tell what u will get after doing this ?

Answer 16

x(x+3)-2(x+3)=(x+3)(x-2)

Answer 17

now on right can u factor numerator ??

Answer 18

do I do FOIL after that?

Answer 19

we foiled left side do on right n tell
??

Answer 20

Ohh, ok I see. Umm I dont think you can factor it anymore.

Answer 21

x^2+5x+4

Answer 22

this term ??

Answer 23

no x(x+3)-2(x+3)=(x+3)(x-2)

Answer 24

Erg, Im sorry. Im honestly just so confused right now :/

Answer 25

\[\frac{ x+1 }{ (x+3)(x-2) }*\frac{ x+4 }{ x^2+5x+4 }\]

Answer 26

we left with this now

Answer 27

ok

Answer 28

x^2+5x+4 we need to foil it

Answer 29

ok

Answer 30

do it lol

Answer 31

I dont know how :/

Answer 32

do i do 4(x^2+5x+4)?

Answer 33

x^2+4x+x+4

Answer 34

4x^2+20x+16

Answer 35

x(x+4)+1(x+4)=(x+4)(x+1)

Answer 36

ok

Answer 37

\[\frac{ x+1 }{ (x+3 )(x-2)}*\frac{ x+4 }{ (x+1)(x+4) }\]

Answer 38

x+1 and x+4 will cancel x+1 and x=4 in numerator

Answer 39

ok

Answer 40

we left with \[\frac{ 1 }{ (x+3)(x-2) }\]

Answer 41

that is our ans

Answer 42

THANKYOU SO MUCH! :D

Answer 43

welcome:)