Medal for answers: http://prntscr.com/52oy2d
\(\large\tt \begin{align} \color{black}{ \text{a quadratic function has degree 2}\\ \color{black}{\huge x^{\color{red}{2}}}\\\\~\\ (2.)\\ y=-(5+2x^2)\\ \text{if u put x=0 here then}\\ \text{y=-5}\\ \text{while all the other graphs start from positive}\\ \text{or zero}\\ \text{so} ~~y=-(5+2x^2)~~ \text{only starts downwards}\\ }\end{align}\)
I got the 2nd one, the answers to #1 are A and C?
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\(\large\tt \begin{align} \color{black}{y=2(x+1)(x-6)\\~\\ }\end{align}\) can u simplify this
Ive tried but I dont know
option c which u ticked is wrong
u can show ur work
I multiply the 2 into (x+1)(x-6) right.. I couldnt get any of the answers
Im doing it wrong
first simplify this \(\Large(x+1)(x-6)\) and show ur work
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