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In a finite group z/3z, why -1̅ = 2̅ ?
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Z/3Z is the group addition modulo 3
which is the set of equivalence classes {0* , 1* , 2*} (i cant draw bars over numbers)
so you can think of this as a clock
Does it work like standard algebra? I know that 2̅+1̅=0, so i subtract -1̅ from both sides and end up with 2̅=-1̅?
|dw:1415047016137:dw|
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What about \[1^{-1}\]
lets define movements as clockwise. so 1* + 1* = 2*
1^-1 + ? = 0 on this clock
1?
define -1 as going counterclockwise 120 degrees. 1+ as a clockwise rotation 120 degrees
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so start from zero
-1 is counterclockwise 120 degrees, where do you end up?
|dw:1415047225805:dw|
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