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Mathematics 28 Online
OpenStudy (anonymous):

In a finite group z/3z, why -1̅ = 2̅ ?

OpenStudy (perl):

Z/3Z is the group addition modulo 3

OpenStudy (perl):

which is the set of equivalence classes {0* , 1* , 2*} (i cant draw bars over numbers)

OpenStudy (perl):

so you can think of this as a clock

OpenStudy (anonymous):

Does it work like standard algebra? I know that 2̅+1̅=0, so i subtract -1̅ from both sides and end up with 2̅=-1̅?

OpenStudy (perl):

|dw:1415047016137:dw|

OpenStudy (anonymous):

What about \[1^{-1}\]

OpenStudy (perl):

lets define movements as clockwise. so 1* + 1* = 2*

OpenStudy (perl):

1^-1 + ? = 0 on this clock

OpenStudy (anonymous):

1?

OpenStudy (perl):

define -1 as going counterclockwise 120 degrees. 1+ as a clockwise rotation 120 degrees

OpenStudy (perl):

so start from zero

OpenStudy (perl):

-1 is counterclockwise 120 degrees, where do you end up?

OpenStudy (perl):

|dw:1415047225805:dw|

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